11x^2-6-2(x^2+4)=2

Solution for 11x^2-6-2(x^2+4)=2 equation:

11x^2-6-2(x^2+4)=2

We move all terms to the left:

11x^2-6-2(x^2+4)-(2)=0

We add all the numbers together, and all the variables

11x^2-2(x^2+4)-8=0

We multiply parentheses

11x^2-2x^2-8-8=0

We add all the numbers together, and all the variables

9x^2-16=0

a = 9; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·9·(-16)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*9}=\frac{-24}{18}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*9}=\frac{24}{18}
=1+1/3
$